# How to Factor Quadratics- A Simplified Explanation Humankind has been slowly uncovering the mysteries of numbers for millennia now. We can trace mathematical learning all the way back to the Babylonians. These ancient peoples developed an impressive understanding of math.

And they lived almost 4,000 years ago, well before the most famous mathematicians even existed.

Now here you are 4,000 years later, trying to factor a quadratic equation. Sadly, you’re not as proficient as the ancient Babylonians and Greeks.

But you can and will learn how to factor quadratics. We’ll make sure of it and do so in the simplest way possible.

Before we actually factor any quadratics, let’s talk about methods you can use to factor them. There’s more than one way to approach factoring quadratics, but not every method works for every quadratic equation.

Generally speaking, there are two methods you can use to factor quadratics. You can factor quadratics by:

2. Inspection

The quadratic formula will always help you factor a quadratic equation. It is, after all, a formula which yields results, given you plug in the correct numbers.

Factoring quadratics by using inspection, on the other hand, isn’t always effective. Some quadratics are too complex to factor via inspection.

## What Is the Quadratic Formula?

So we’ve established two primary methods of factoring quadratics. Let’s now go over the quadratic formula in more detail. Recall that a quadratic equation takes the form:

ax^(2) + bx + c = 0, where a, b, and c are constants. The quadratic formula uses these three constants to calculate the value(s) of the variable x. The formula is as follows:

x = (-b +/- sqrt(b^(2) – 4ac)) / 2a

There are a few things to note here, the first of which is that “-b” refers to the opposite of “b.” So if “b” is -7, “-b” is 7.

The second thing to note is that the “+/-” component of the formula indicates that you’ll be solving two separate equations. These equations are:

• x = (-b + sqrt(b^(2) – 4ac)) / 2a
• x = (-b – sqrt(b^(2) – 4ac)) / 2a

In other words, the formula yields two separate values. Both of these values are “roots” or “zeros.”

## What Does the Formula Calculate?

Simply put, a root is any value for x which makes a quadratic expression equal “0.” Take, for instance, the quadratic expression:

x^(2), where a = 1, b = 0, and c = 0

There’s only one value which would make this expression equal “0.” That’s right. You guessed it: x would have to be “0.” So this quadratic equation has one zero instead of two.

Which leads us to an important point:

Not every quadratic equation has two zeros. While many have two zeros, some only have a single unique zero.

Let’s try another example:

x^(2) – x, where a = 1, b = -1, and c = 0

Again, if x = 0, this expression simplifies to “0.” And there’s another value in this case which yields the same result: 1. So this quadratic has two zeros.

Graphically, we can see these zeros if we plot some points for each equation. How so?

When x is equal to a quadratic equation’s zero, that quadratic equation’s graph (called a parabola) crosses the x-axis. Let’s apply this logic to the two examples we just completed together.

In the case of x^(2), where the only zero is “0,” the equation’s graph only crosses the x-axis at x = 0. And in the case of x^(2) – x,, where the two zeros are “0” and “1,” the equation’s graph crosses the x-axis at both x = 0 and x = 1.

Now let’s put this formula to use by looking at a real quadratic equation. Let’s say our equation is:

x^(2) -2x + 4 = 0, where a = 1, b = -2, and c = 4

We know that the quadratic formula is:

x = (-b +/- sqrt(b^(2) – 4ac)) / 2a

So let’s plug in our values for a, b, and c:

x = (2 +/- sqrt((-2)^(2) – 4(1)(4))) / 2(1)

Simplifying, we get:

x = (2 +/- sqrt(-12)) / 2)

We now separate our two expressions:

• x = (2 + sqrt(-12)) / 2)
• x = (2 – sqrt(-12)) / 2)

In this case, the equation’s two zeros will be imaginary numbers. That’s nothing, however, to freak out about. So, no, you’re not bad at math because you got wonky numbers.

## What to Do with the Zeros

Okay. So you have a bunch of zeros. How are these zeros going to help you factor a quadratic equation?

Consider the examples we’ve completed thus far. We’ll start with the equation x^(2) – x.

As we determined earlier, the equation has two zeros: 0 and 1. Recall that when x is equal to a zero, a quadratic equation simplifies to “0.” So we need to ask ourselves what we can do to those values of x to make them equal zero.

Well, the first zero is already zero, so you don’t have to do anything to it. The second zero, on the other hand, is “1.” In order to make this number “0,” we have to subtract “1” from it.

By this logic, the equation’s factors must be:

• x
• (x – 1)

In other words, the factorization of x^(2) – x is:

x(x-1)

Notice that when x = 0,the entire factorization simplifies to zero. The same is true when x = 1.

The fact that those expressions simplify to “0” when you plug in the zeros is what makes this factorization correct. If you plug your zeros into your factorization and it doesn’t evaluate to “0,” you’ve done something wrong.

## How to Factor Trinomials and Binomials by Inspection

Let’s get one thing straight: You’re not going to factor many quadratic equations by inspection. Some equations, however, are easy to solve by inspection. Consider the following equation:

x^(2) – 4, where a = 1, b = 0, and c = -4

Notice that there’s no “b.” Also pay attention to the fact that x^(2) and “4” are perfect squares. The sqrt(x^(2)) = x while the sqrt(4) = 2.

Using this information, you might be able to see that the factorization is:

(x + 2)(x – 2)

If you multiply these factors, you’ll see why the “b” component doesn’t exist:

(x + 2)(x – 2) –> x^(2) – 2x + 2x – 4 –> x^(2) – 4

The two middle terms evaluate to zero.